[Koha] Koha 16.05 - SQL Report on Koha Control Numbers - Finding blank 001s

[Paul A]

On 2/8/2017 12:14 PM, Craig Butosi wrote:
> Hi Paul,
>
> Thanks very much for this. Your query actually helped me to identify my syntax problem. I was using "IS NOT NULL" in my WHERE clause, which includes the XML for 001, when I should have been using "= 0", as in:
>
> SELECT biblionumber
> FROM biblioitems
> WHERE EXTRACTVALUE(marcxml,'//controlfield[@tag="001"]') = 0
>
> The above query successfully returns all biblionumbers with no 001s.

Perhaps accidental serendipity? It's highly unlikely that you have any 
001s with 0 as value, so it works... In fact my query looks for the 
COUNT, so "= 0" (no records) can be replaced by "> 1" and find duplicate 
records ;=}

Warmest regards -- Paul
>
> Thanks for your time on this!
>
> All best,
>
> Craig Butosi, MA, MLIS, B Mus (Hons.)
> LIBRARY SERVICES MANAGER
> THE ROYAL CONSERVATORY
> TELUS Centre for Performance and Learning
> 273 Bloor Street West
> Toronto, ON M5S 1W2
> 416.408.2824 x338
> www.rcmusic.ca
>
> -----Original Message-----
> From: Koha [mailto:koha-bounces at lists.katipo.co.nz] On Behalf Of Paul A
> Sent: February-08-17 11:54 AM
> To: koha at lists.katipo.co.nz
> Subject: Re: [Koha] Koha 16.05 - SQL Report on Koha Control Numbers - Finding blank 001s
>
> On 2/8/2017 11:13 AM, Craig Butosi wrote:
>> Hi all,
>>
>> Koha 16.05 o Ubuntu 14.04 LTS
>> Package install
>>
>> Would a kind soul help me with a basic SQL report which compiles a list of all bibliographic records that have a blank 001, but which have a biblionumber? Columns selected for the report = biblionumber, title, author.
>>
>> I have tried a number of queries but can't seem to get the syntax correct.
>
> We have one that just gives you "clickable links" to allow editing the
> biblio:
>
> SELECT GROUP_CONCAT('<a target="_blank" href=\"/ cgi-bin/koha/cataloguing/addbiblio.pl?biblionumber=',biblionumber,'\">',biblionumber,'</a>'
> SEPARATOR ', ')
> AS BibNums,
> EXTRACTVALUE(marcxml,'//controlfield[@tag="001"]') AS Id FROM biblioitems GROUP BY Id HAVING count(Id) = 0;
>
> Best -- Paul
>
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