Re: [Koha] [KOHA] SQL CIRCULATION REPORT- how to SUM
Hi Rogan, I reintroduced two filters date abd itemtype. So that i can sekect any date be it weekly monthly or quarterly etc. I also have different itemtypes sone of which do not start wih a digit and I need to filter them out yo get accurate results. (Your advice on whether the filters might be sn issue is verywelcome) Below is my query. SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS", count(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') AND date(datetime) BETWEEN <<Date BETWEEN (yyyy-mm-dd)|date>> AND <<and (yyyy-mm-dd)|date>> AND items.itype = <<Item type|itemtypes>> GROUP BY SUBSTRING(itemcallnumber,1,1) UNION ALL SELECT "TOTAL" AS "CLASS", SUM(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') Sent from my Samsung Galaxy smartphone.-------- Original message --------From: rogan.hamby@gmail.com Date: 15/03/2020 00:48 (GMT+03:00) To: muiru james <muirunyeri@gmail.com>, Koha <koha@lists.katipo.co.nz> Subject: Re: [KOHA] SQL CIRCULATION REPORT- how to SUM Hi James, The query I posted worked with my quick test. Could you post your query as it is now? On Sat, Mar 14, 2020 at 9:52 AM muiru james <muirunyeri@gmail.com> wrote: Hi Rogan and All, I cant thank you enough for the tremendous effort you have put towards helping me solve my problem. You do indeed understand well what I need. The UNION ALL is working well by adding a new row below the last class group. However the SUM function is returning a 0 (zero). It seems its not adding up the numbers. Please dont give up but help me find out the last remaining bit. We are almost there. Most appreciated James On Thu, Mar 12, 2020 at 2:57 PM <rogan.hamby@gmail.com> wrote: Hi James, If I'm understanding correctly you want an additional row giving a sum of all the numbers in addition to the per class one? The simplest way it occurs to me to do that is with a UNION ALL statement. I've taken some filters out for brevity but this illustrates the approach: SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS", count(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') GROUP BY SUBSTRING(itemcallnumber,1,1) UNION ALL SELECT "All Classes" AS "CLASS", SUM(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') Basically with UNION ALL you can create other queries that don't have to be tied to the data of the previous queries so long as the columns line up. On Thu, Mar 12, 2020 at 3:04 AM muiru james <muirunyeri@gmail.com> wrote: Hi Rogan and Team, I really appreciate your assistance towards my problem. The query does indeed work to answer my need. Another query was also pushed to me towards the same. I'm now looking for a way to SUM my answer to get the total number of books issued. Any suggestions would be most welcome for any of the 2 queries. The other SQL query is as below: - SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS", count(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') AND date(statistics.datetime) BETWEEN <<Date BETWEEN (yyyy-mm-dd)|date>> AND <<and (yyyy-mm-dd)|date>> AND statistics.itemtype = 'BK' GROUP BY SUBSTRING(itemcallnumber,1,1) ORDER BY items.itemcallnumber ASC N.B My desire is to SUM the NUMBER column as TOTAL. Please assist team Warm Regards. JAMES On Fri, Mar 6, 2020 at 7:10 PM <rogan.hamby@gmail.com> wrote: Hi James, One simple way to handle it is with a case statement. The following example has a static between filter for the dates but it illustrates this approach. You can also do some cleaning to make sure there aren't spaces in front and it assumes that all of your DDC numbers in fact start with a digit. SELECT COUNT(*), CASE WHEN LEFT(it.itemcallnumber,1) = '0' THEN '000s' WHEN LEFT(it.itemcallnumber,1) = '1' THEN '100s' WHEN LEFT(it.itemcallnumber,1) = '2' THEN '200s' WHEN LEFT(it.itemcallnumber,1) = '3' THEN '300s' WHEN LEFT(it.itemcallnumber,1) = '4' THEN '400s' WHEN LEFT(it.itemcallnumber,1) = '5' THEN '500s' WHEN LEFT(it.itemcallnumber,1) = '6' THEN '600s' WHEN LEFT(it.itemcallnumber,1) = '7' THEN '700s' WHEN LEFT(it.itemcallnumber,1) = '8' THEN '800s' WHEN LEFT(it.itemcallnumber,1) = '9' THEN '900s' ELSE 'OTHER' END from (SELECT * FROM issues UNION ALL SELECT * FROM old_issues) i JOIN items it ON it.itemnumber = i.itemnumber WHERE DATE(i.timestamp) BETWEEN '2020-02-01' AND '2020-02-29' GROUP BY 2 ORDER BY 2; On Thu, Mar 5, 2020 at 11:06 AM muiru james <muirunyeri@gmail.com> wrote: Dear All, My library uses DDC scheme of classification and we are looking for a report that will count items checked out allowing us to select day(s) of issue, select itemtype and group the statistics by DDC 10 broad classes. *EXAMPLE* IN a date range say 1st-31st March 2020. *DDC Class | NO. of books issued* 000 - 12 100 - 26 200 - 157 . . . 900 - 230 The report can generate statistics for a day, month, quarter, e.t.c. Any assistance however close will be greatly appreciated. Thank you as you prepare to help James _______________________________________________ Koha mailing list http://koha-community.org Koha@lists.katipo.co.nz Unsubscribe: https://lists.katipo.co.nz/mailman/listinfo/koha
Hi James, A few thoughts from skimming it. 1) I don't see where you're using biblioitems anywhere in the report unless I'm just not seeing it so you probably don't need it for a join. I don't think it'll hurt anything other than slow the report less than you'll even notice but still ... if not needed I'd cut it out. 2) you're going to want the same filters in the second query as the first to make sure you get the same numbers 3) you are using a SUM on the statistics type but you can only sum numbers you probably want a COUNT there, which you do in the first query but not the second On Sun, Mar 15, 2020 at 12:38 AM muirunyeri <muirunyeri@gmail.com> wrote:
Hi Rogan,
I reintroduced two filters date abd itemtype. So that i can sekect any date be it weekly monthly or quarterly etc. I also have different itemtypes sone of which do not start wih a digit and I need to filter them out yo get accurate results. (Your advice on whether the filters might be sn issue is verywelcome)
Below is my query.
SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS", count(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') AND date(datetime) BETWEEN <<Date BETWEEN (yyyy-mm-dd)|date>> AND <<and (yyyy-mm-dd)|date>> AND items.itype = <<Item type|itemtypes>> GROUP BY SUBSTRING(itemcallnumber,1,1) UNION ALL SELECT "TOTAL" AS "CLASS", SUM(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew')
Sent from my Samsung Galaxy smartphone. -------- Original message -------- From: rogan.hamby@gmail.com Date: 15/03/2020 00:48 (GMT+03:00) To: muiru james <muirunyeri@gmail.com>, Koha <koha@lists.katipo.co.nz> Subject: Re: [KOHA] SQL CIRCULATION REPORT- how to SUM
Hi James,
The query I posted worked with my quick test. Could you post your query as it is now?
On Sat, Mar 14, 2020 at 9:52 AM muiru james <muirunyeri@gmail.com> wrote:
Hi Rogan and All,
I cant thank you enough for the tremendous effort you have put towards helping me solve my problem.
You do indeed understand well what I need.
The UNION ALL is working well by adding a new row below the last class group. However the SUM function is returning a 0 (zero). It seems its not adding up the numbers.
Please dont give up but help me find out the last remaining bit. We are almost there.
Most appreciated
James
On Thu, Mar 12, 2020 at 2:57 PM <rogan.hamby@gmail.com> wrote:
Hi James,
If I'm understanding correctly you want an additional row giving a sum of all the numbers in addition to the per class one? The simplest way it occurs to me to do that is with a UNION ALL statement. I've taken some filters out for brevity but this illustrates the approach:
SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS", count(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') GROUP BY SUBSTRING(itemcallnumber,1,1) UNION ALL SELECT "All Classes" AS "CLASS", SUM(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew')
Basically with UNION ALL you can create other queries that don't have to be tied to the data of the previous queries so long as the columns line up.
On Thu, Mar 12, 2020 at 3:04 AM muiru james <muirunyeri@gmail.com> wrote:
Hi Rogan and Team,
I really appreciate your assistance towards my problem. The query does indeed work to answer my need. Another query was also pushed to me towards the same.
I'm now looking for a way to SUM my answer to get the total number of books issued. Any suggestions would be most welcome for any of the 2 queries. The other SQL query is as below: -
SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS", count(statistics.type) AS 'NUMBER' FROM borrowers LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber) LEFT JOIN items ON (items.itemnumber = statistics.itemnumber) LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber = items.biblioitemnumber) WHERE statistics.type IN ('issue', 'renew') AND date(statistics.datetime) BETWEEN <<Date BETWEEN (yyyy-mm-dd)|date>> AND <<and (yyyy-mm-dd)|date>> AND statistics.itemtype = 'BK' GROUP BY SUBSTRING(itemcallnumber,1,1) ORDER BY items.itemcallnumber ASC
N.B My desire is to SUM the NUMBER column as TOTAL.
Please assist team
Warm Regards. JAMES
On Fri, Mar 6, 2020 at 7:10 PM <rogan.hamby@gmail.com> wrote:
Hi James,
One simple way to handle it is with a case statement. The following example has a static between filter for the dates but it illustrates this approach. You can also do some cleaning to make sure there aren't spaces in front and it assumes that all of your DDC numbers in fact start with a digit.
SELECT COUNT(*), CASE WHEN LEFT(it.itemcallnumber,1) = '0' THEN '000s' WHEN LEFT(it.itemcallnumber,1) = '1' THEN '100s' WHEN LEFT(it.itemcallnumber,1) = '2' THEN '200s' WHEN LEFT(it.itemcallnumber,1) = '3' THEN '300s' WHEN LEFT(it.itemcallnumber,1) = '4' THEN '400s' WHEN LEFT(it.itemcallnumber,1) = '5' THEN '500s' WHEN LEFT(it.itemcallnumber,1) = '6' THEN '600s' WHEN LEFT(it.itemcallnumber,1) = '7' THEN '700s' WHEN LEFT(it.itemcallnumber,1) = '8' THEN '800s' WHEN LEFT(it.itemcallnumber,1) = '9' THEN '900s' ELSE 'OTHER' END from (SELECT * FROM issues UNION ALL SELECT * FROM old_issues) i JOIN items it ON it.itemnumber = i.itemnumber WHERE DATE(i.timestamp) BETWEEN '2020-02-01' AND '2020-02-29' GROUP BY 2 ORDER BY 2;
On Thu, Mar 5, 2020 at 11:06 AM muiru james <muirunyeri@gmail.com> wrote:
Dear All,
My library uses DDC scheme of classification and we are looking for a report that will count items checked out allowing us to select day(s) of issue, select itemtype and group the statistics by DDC 10 broad classes.
*EXAMPLE*
IN a date range say 1st-31st March 2020.
*DDC Class | NO. of books issued* 000 - 12 100 - 26 200 - 157 . . . 900 - 230
The report can generate statistics for a day, month, quarter, e.t.c.
Any assistance however close will be greatly appreciated.
Thank you as you prepare to help
James _______________________________________________
Koha mailing list http://koha-community.org Koha@lists.katipo.co.nz Unsubscribe: https://lists.katipo.co.nz/mailman/listinfo/koha
participants (2)
-
muirunyeri -
rogan.hamby＠gmail.com