help needed I need a complete patron list with item.barcodes (items still with that patron). this report should also include the patrons which don't have any item with them. what i made isSELECT borrowernumber,borrowers.cardnumber,borrowers.surname,borrowers.firstname,borrowers.address,borrowers.address2,borrowers.branchcode,borrowers.categorycode,borrowers.dateenrolled,borrowers.dateexpiry,borrowers.debarredcomment,borrowers.borrowernotes,items.barcodeFROM borrowers LEFT JOIN items but there is a syntax error, i don't know where?Monisa Aslam
help needed I need a complete patron list with item.barcodes (items still with
Hi Monisa that patron). this report should also include the patrons which don't have any item with them.
what i made isSELECT borrowernumber,borrowers.cardnumber,borrowers.surname,borrowers.firstname,borrowers.address,borrowers.address2,borrowers.branchcode,borrowers.categorycode,borrowers.dateenrolled,borrowers.dateexpiry,borrowers.debarredcomment,borrowers.borrowernotes,items.barcodeFROM borrowers LEFT JOIN items but there is a syntax error, i don't know where?Monisa Aslam
There is no direct connection between tables "borrowers" and "items", but table "issues" contains both borrowernumber and itemnumber, so you will have to start with something like this: SELECT borrowers.borrowernumber, items.itemnumber, items.barcode FROM borrowers LEFT JOIN issues ON borrowers.borrowernumber=issues.borrowernumber LEFT JOIN items ON issues.itemnumber=items.itemnumber ORDER BY borrowers.borrowernumber, items.itemnumber It will give you a list like this: +----------------+------------+----------+ | borrowernumber | itemnumber | barcode | +----------------+------------+----------+ ... | 2122 | NULL | NULL | | 2123 | NULL | NULL | | 2124 | 1163 | 74042220 | | 2124 | 5839 | 74112730 | | 2124 | 14127 | 00000826 | | 2124 | 14156 | FERN0057 | | 2124 | 14211 | FERN0060 | | 2125 | NULL | NULL | ... Also I advise to learn about the SQL syntax of JOIN since it doesn't work by just putting the name of a table after JOIN. For example here: http://www.w3schools.com/sql/sql_join.asp Hope this helps. Best wishes: Michael -- Geschäftsführer · Diplombibliothekar BBS, Informatiker eidg. Fachausweis Admin Kuhn GmbH · Pappelstrasse 20 · 4123 Allschwil · Schweiz T 0041 (0)61 261 55 61 · E mik@adminkuhn.ch · W www.adminkuhn.ch
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Michael Kuhn -
Monisa Aslam